int y=1, x, *p, a[ ]={2,4,6,8,10};
	p=&a[1];
	for(x=0;x<3;x++)
	y + = * (p + x);
	printf("%d\n",y);
	程序的輸出結(jié)果y的值是()
 
                            	for (a=1,b=1;a<=100;a++) 
	{ if(b>=20)   break; 
	if(b%3==1) 
	{b+=3;  continue;} 
	b-=5;                      }  
	程序的輸出結(jié)果a的值為()
