A.2 B.4 C.5 D.6
A.B+B+B=3B B.A+(B•c•D.=(A+B.•(A+C.•(A+D. C.A•(A+B+C.=2A+AB+AC D.(A+B.’=A’+B’
A.0.5% B.1% C.1.5% D.2%